Ответы и объяснения

2012-06-03T18:22:28+04:00

cos2x=0
2x=π/2+πn; n ε Z.
x=π/4+πn/2,  n ε Z.

sinx =√3/2

х=(-1)^n*π/3+πn n ε Z.

2012-06-03T19:22:26+04:00

cos2x = 0

2x = π/2 + πn

x = π/4 + πn/2

sinx = √3/2

x = (-1)^n * arcsin√3/2 + πn

x = (-1)^n * π/3 + πn