Ответы и объяснения

2014-02-14T22:22:18+04:00
\left \{ {{y=x+2} \atop {x(x+2)-x-2-10=0}} \right. \left \{ {{y=x+2} \atop {x^2+x-12=0}} \right. 
x^2+x-12=0
D=1+48=49
x1=-4 
x2=3
 \left \{ {{ \left \{ {{y1=2-2} \atop {x1=-4}} \right. } \atop { \left \{ {{y2=5} \atop {x2=3}} \right. }} \right.