Ответы и объяснения

2014-01-03T14:50:07+04:00
=1/2*log ab_(a) -log ab_(b) +2*log ab_(b^1/2) - 2*log ab_(a)=
=1/2*log ab_(a) - log ab_(b) + log ab_(b) - 2*log ab_a=
=-3/2*log(ab)_(a)= -3/2 * log a_a / log a_(ab)= -3/2 /(log a_a +log a_(b))=
=-3/2 / (1 +log a_(b))= -3/2/(1+0,5)=-3/2 / 3/2= -1