Ответы и объяснения

2013-12-12T19:46:45+04:00
X^2(x^2-16)=0                         Пусть y^2=t
x=0 или x^2-16=0                   4t^2+7t-2=0
x^2=16                                  D=81
x=-4 x=4                               t1=1/4
                                            t2=-2
                                            y^2=1/4 или y^2неравен-2
                                             y=-корень из1/4 y=корень из 1/4