Ответы и объяснения

  • fuflunce
  • почетный грамотей
2012-12-04T22:40:48+04:00

64 = 2^6
 (2^6)/[2^(6/9)] - 2^(6/18) =
= (2^6)/2^(2/3) - 2^(1/3) =
= 2^(6-2/3) - 2^(1/3) =
= 2^(16/3) - 2^(1/3) =
= 2^(1/3)*[2^(16/3-1/3) - 1]  =   [выносим за скобки 2^(1/3)]

= 2^(1/3)*(2^5 - 1) = 
 =2^(1/3)*(32 - 1) = 2^(1/3)*31  [записать 2^1/3 как корень кубич. из 2]